48x^2-16x=35x^2

Solution for 48x^2-16x=35x^2 equation:

48x^2-16x=35x^2

We move all terms to the left:

48x^2-16x-(35x^2)=0

determiningTheFunctionDomain
48x^2-35x^2-16x=0

We add all the numbers together, and all the variables

13x^2-16x=0

a = 13; b = -16; c = 0;
Δ = b2-4ac
Δ = -162-4·13·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-16}{2*13}=\frac{0}{26}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+16}{2*13}=\frac{32}{26}
=1+3/13
$